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(1/16)^3x=64^2(x+8)
We move all terms to the left:
(1/16)^3x-(64^2(x+8))=0
Domain of the equation: 16)^3x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/16)^3x-(64^2(x+8))=0
We multiply all the terms by the denominator
(+1-((64^2(x+8)))*16)^3x=0
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